Thursday, March 01, 2012

Class Topics: 03.01.12

In EDM today, students continued their work with Pre-Algebra skills by discussing Lesson 1.8: Graphing on the Coordinate Plane.  Before beginning the lesson, students asked clarifying questions about last night's homework since Lesson 1.7 was self-directed.  This lesson ties in nicely to some of our previous work with ordered pairs (x,y) and from yesterday's lesson on solving for y by using substitution.
Our Learning Intentions for today:
  • I will be able to identify the x and y-axis on a coordinate plane.
  • I will be able to give the coordinates of a specific point on a coordinate plane.
  • I will be able to graph the solutions to a given equation when the x value is listed.
In class, students...
  • constructed on coordinate plane on graph paper and plotted ordered pairs generated from a given equation.
  • collaborated with peers to compare and check answers.
For Evening Practice, students CAN...
  • complete Reteach and Practice 1.8.
  • complete the two Khan Links assigned on Monday that are due on Friday.

In Pre-Algebra today, students prepared for their Chapter Seven Mid-Quiz by working with proportions.  During the lesson, students were introduced to setting-up proportions and utilizing the cross product method to solve for missing values.  Lesson 7.4: Solving Proportions, modeled several examples that students were able to view and discuss.  
Our Learning Intentions for today:
  • I will be able to determine whether two ratios are proportional using the cross products method.
  • I will be able to apply the use or ratios and proportions to solve problems such as the one listed below.
    • A mixture of fuel for a certain small engine should be 4 parts gasoline to 1 part oil.  If you combine 5 quarts of oil with 15 quarts of gasoline, will the mixture be correct? 
  • I will be able to calculate for one of the four missing numbers in a proportion by using the cross product method to set up a one-step equation.
In class, students...
  • collaborated with a peer(s) to complete Problem Solving 7.4.
  • began their Evening Practice.
For Evening Practice, students CAN...
  • solve and post their response to the two blog questions posted below.
  • utilize the quiz prep section in the textbook to study for tomorrow's ten question quiz.
    • Robert weighs 90 lbs and sits on a seesaw 5 ft away from its center. If Sharon sits 6 ft away from the center and the seesaw is balanced, how much does Sharon weigh? 
    •  In a shipment of 400 parts, 14 are found to be defective. How many defective parts should be expected in a shipment of 1000?


25 comments:

  1. sharon weighs 108 pounds

    35 are defective

    Joey

    ReplyDelete
  2. 1. For number one I took 90 times by 6 and got 540. Then I took 540 divided by 5 and got 108. To check my answer I made sure each side was equal, which they were so Sharon weighs 108 pounds.

    2. For number two I took 14 times 1,000 and got 14,000. Then divided by 400 and got 35. Then I made sure both sides were equal. For an answer I got 35 defective parts in a shipment of 1,000 parts.
    Deuce

    ReplyDelete
  3. 1. Sharon weighs 75 pounds
    2. There should be 35 defective parts.

    Volks

    ReplyDelete
  4. 1. Sharon ways about 75 pounds

    2. There should be about 35 defective parts.

    Matt

    ReplyDelete
  5. 1)108 LBS
    2)28 parts


    Fran

    ReplyDelete
  6. 1. Sharon weighs 75 pounds.
    2. There should be 35 defective parts.





    STRINGER

    ReplyDelete
  7. 1.) Sharon weighs 108 pounds

    2.) 35 defective parts


    IZZY

    ReplyDelete
  8. 1) Sharon weighs 108 ibs.
    2) 35 pieces are expected to be broken.


    Rish Fish :)

    ReplyDelete
  9. 1. Sharon weighs 108lbs.
    2. There should be 35 defective parts.
    ~Dalgleish~

    ReplyDelete
  10. 1. Sharon weighs 108 pounds

    2. About 35 defective parts



    ~Cheesy Ninja

    ReplyDelete
  11. 1- 108 lbs
    2- 35 defective parts

    D-Will

    ReplyDelete
  12. For question one, I just want to say that I hope Robert is around or under the age of ten, because if he is older than that, I think there's a problem and Robert should start storing up for the winter...and every other season. But, anyway, here are my answers:

    1. Sharon weighs 108 lbs.

    2. There should be 35 defective parts expected in a shipment of 1000 parts.

    Syd

    ReplyDelete
  13. I love the additional comments Syd; they made me laugh out loud.

    Deuce, I liked how you took me through your process of solving the problem. It helps me understand/see how you are thinking about the problem.

    ReplyDelete
    Replies
    1. 1. Sharon weighs about 108 pounds.
      2. There is about 35 defective parts in a shipment of 1000 parts
      :p :D

      Dichosa

      Delete
  14. For question one, I got 108 pounds by making fractions and cross multiplying. I cross multiplied 90/5 and x/6, and got a total of 540 divided by 5x. I then divide 540 by five and get an answer of 108 pounds.

    For question two, I got 35 defective parts by making fractions and multiplying across again. the fractions are 400/14 and 1000/x. I then cross multiplied 14 and 1000, getting 14000, and 400 and x, giving me 400x. I then divided 14000 by 400, therefore getting an answer of 35 defective parts.

    Higgs

    ReplyDelete
  15. 1) 108 lbs
    2) 35 defective parts

    Yogurt

    ReplyDelete
  16. 108 lbs
    35 defective parts
    sorry I accidantly sent a post that i didn't sighn my name.

    Jared 6 period

    ReplyDelete
  17. 1)5/90=6/w, 5w=90(6), 5w=540, 5w/5 cancels out, 540/5=108, w=108lbs
    2)14/400=d/1000, 400d=1000(14), 400d/400 cancels out, 1400/400=35, d=35 defective parts

    Taylor Hubert

    ReplyDelete
  18. 1. Well I tried to solve for Sharon's weight the way the book showed it and got 75 lb. Then, I tried to solve it the way I thought we were supposed to solve this kind of problem and got 108 lb. I'm not sure which one is the correct answer!

    2. 35 defective parts: I got this answer by setting up the ratio 14/400 = p/1000. Next I cross multiplied to get 400p = 14,000. Finally I isolated p by dividing each side by 400. 14,000 divided by 400 equals 35.

    Balthaser

    ReplyDelete
  19. 1) she weighs 108 lbs

    2) 35 parts

    Gen Mayer

    ReplyDelete
  20. Q 1.)90lbs * 6ft = 540 then divide 540 by 5 = 108 lbs.

    Q.2) 400 * 2.5 = 1000 so 14 * 2.5 = 35 defective parts

    Diggity

    ReplyDelete
  21. (1. Sharon would weigh 108 pounds.You would take 6ft and multiply it by 90 pounds. That's 540. Then take 540 and divide that by 5ft. 108 pounds.

    (2. 35 defective parts
    400+400+200=1000
    14 + 14 + 7 = 35

    Jaret.H

    ReplyDelete
  22. 1) Sharon weighs 108 lbs.
    2) 35 parts should be defective.

    Graney

    ReplyDelete
  23. 1) Sharon weighs 108 pounds
    2) 35 defective parts

    -Cole

    ReplyDelete