The heart rate of a hibernating woodchuck slows from 80 to 4 beats
per minute. What is the percent decrease of the woodchuck's
heart rate when hibernating?
During 2°, students reviewed the Evening Practice with an answer key provided by Mr. Giomini. Students were then practiced more with Lesson 5.4: Dimensional Analysis. This lesson is the most challenging of the chapter and caused us some mental pain. To model this skill, we utilized a link that Miss McGreer found to help us with the different jumps in units. Click here to use the link at home.
- 1, 3, and 4° -
- determine the percent increase or decrease.
- divide whole numbers.
- convert between fractions, decimals, and percents.
- 2° -
- set-up a proportion from given information.
- make conversions between different units of measure.
- solve word problems using dimensional analysis
For Evening Practice, the student is expected to...
- 1, 3, and 4° -
- complete the Khan Skills linked below:
- Mark Up and Commission Word Problems (Due by Friday morning!)
- complete Lesson 6.5 Practice C (odd).
- 2° -
- complete Lesson 5.3 Problem Solving.
My answer is 105.2631579%
ReplyDeleteYou divided wrong. Try again
DeleteThe answer is that the woodchuck heart beat slows down 95% when it hibernates.
ReplyDeleteGreat job Gruber! You are so intelligent!
DeleteThe answer is 95% I got it by subtract 80 by 4 to get 76 simplified it to 19/20 and multiplied both by five to get a 95% difference
ReplyDeleteFolds
answer is 95%. you subtract 4 by 80 and get 76 and then divide 76 by 80.
ReplyDeleteColeman
I got the answer of 95% by taking the original - new price.
ReplyDelete-Sherrill