Tuesday, October 02, 2012

Class Topics: 10.02.12

In Math Six today, students in second period reviewed different material for tomorrow's Unit Two-Mid Point Quiz.  Some of the material that you will find on the assessment are listed below:
  • Standard Notation
  • Number-and-word Notation
  • Adding and Subtracting Decimals
  • Multiplying Decimals
  • Powers of 10 with Positive and Negative Exponents
Fourth period Math Six students began working in Lesson 2.7: Division of Whole Numbers.  Students began class by viewing the video posted below.  The teacher then modeled the skill using Khan Academy.  In class, students independently worked to complete Math Journal pages sixty-six and sixty-seven.  
Today's Learning Intentions: The student will be able to...
  1. review various concepts from Lesson 2.1 through 2.6.
  2. estimate the quotient for different division problems.
  3. use the division algorithm to solve various problems.
For Evening Practice, it is suggested that students...
  1. view the various videos posted to the blog.  (Second Period)
  2. complete Study Link 2.6: Multiplying Decimals.  (Fourth Period / NO CALCULATOR)
  3. complete Khan Skill by Friday.
In Pre-Algebra today, students reviewed last Friday's Weekend Practice by viewing the video posted below.  Once that was completed, students then collaborated with peers to begin their Chapter Two Summative Posttest review by completing pages 100 and 101 in their Pre-Algebra textbooks.  
Today's Learning Intentions: The student will be able to...
  1. apply concepts of: integer computations, inequality interpretation, multiplication and division of exponents and scientific notation to real-world problems.
For Evening Practice, it is suggested that students...
  1. complete the following Khan Skill:


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3 comments:

  1. AnonymousOctober 2, 2012 at 4:39:00 PM EDT

    (3+2)^4/5(7-2)^3=1 because 3+2=5 and 5^4=625 and 7-2=5 so 5^1*5^3=5^4, finally 625/625=1

    Brock Lesner

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  2. AnonymousOctober 2, 2012 at 7:43:00 PM EDT

    Dear Mr. Giomini
    On your video for 3rd period, you said that the equation (3+2)to the 4th power/5(7-2)to the power of 3 was our homework to explain how I got 1, this is how I got 1,
    3+2=5 and 5 the the power of 4 is 625,7-2=5 and 5 to the power of 3 is 125, and 125x5= 625(also 5(7-2) to the power of 3 can also be 5 to the 4th power) and 625/625=1

    ~Schulte

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  3. AnonymousOctober 2, 2012 at 8:34:00 PM EDT

    First you do 3+3=5, so thats 5 to the forth power and that is 625. Then you do 7-2+=5, and then you have 5*5 to the third power, and that is 625. Then you do 625/625=1

    ReplyDelete

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