Wednesday, March 13, 2013

Class Topics: 03.13.13

In Math Six and Pre-Algebra today, students reviewed their Evening Practice from last night and entered in their answers to the Spring Learwood Assessment online.  Once that was completed, students had an opportunity to begin their Evening Practice.
Today's Learning Goals: The student will be able to...
  1. apply test-taking strategies to solve mathematical problems.
  2. determine the measure of central tendency that best reflects a set of data.
  3. calculate missing angles for  various polygons.
  4. use The Pythagorean Theorem to find a missing hypotenuse.  
  5. simplify equations by combing like terms. 
  6. convert between scientific notation and standard notation.
  7. determine the probability of drawing a card.  
For Evening Practice, the student is to complete...
  1. Math Six
    • view the video posted below.
    • complete the handout on Rolling Dice.  CLICK HERE
  2. Pre-Algebra
    • Problem Solving 9.1- CLICK HERE
    • post answers to the questions below.
    • preview Chapter Nine powerpoints for Friday's Pretest.  CLICK HERE


Pre-Algebra Questions

38 comments:

  1. Mr. Giomini,
    For the first question, the probability of 1 or 2 occurring is 0.351. The second question, the probability of 3 not occurring is 0.874. For the third question, the probability of 2,3, or 4 occurring is 0.704.

    Pishner

    ReplyDelete
    Replies
    1. The third one should be 0.794

      Pishner

      Delete
  2. The answer for number one is 35.1 percent. The second answer is 47.7 percent. The finale answer is 79.4 percent.

    Baugh

    ReplyDelete
  3. 1. 35.1%

    2. 87.4%

    3. 79.4%
    Your friend BANGS

    ReplyDelete
  4. Mr. Giomini,
    These are the answers for the blog post.

    1. You add 0.024 and 0.327 and you get, 0.351.
    2. You the probabilities except for the 3rd outcome and you get, 0.874.
    3. You add the outcomes 2, 3, 4 together and get, 0.794. -Wikipedia

    ReplyDelete
  5. 1.0.024+0.375= 0.351%
    2.1-0.126= 0.847%
    3.0.372+0.126+0.341= 0.794%

    Madigan

    ReplyDelete
  6. 1 or 2 - 0.351

    3-0.874

    2 3 4-0.794

    Barone

    ReplyDelete
  7. 1)35.1%
    2) 87.4%
    3) 79.4%
    kauf

    ReplyDelete
  8. 1. 35.1%

    2. 87.4%

    3. 79.4%

    zimms

    ReplyDelete
  9. 1)35.1%
    2) 87.4%
    3) 79.4%
    kauf

    ReplyDelete
  10. 1) 0.351

    2) 0.874

    3) 0.794

    Thieken~

    ReplyDelete
  11. Mr. Giomini

    For 1 and 2 occurring ~ 35.1%
    For 3 not occurring ~ 87.4%
    For 2,3,4 occurring ~ 79.4%

    ~Brion

    ReplyDelete
  12. 1. 35%
    2. 87.4%
    3. 63.5

    Josh A.

    ReplyDelete
  13. 1 and 2 have a 0.361 chance of occurring
    3 has a 0.874 chance of not happening
    2,3, and 4 have a chance of 0.794 occurring

    Stewart

    ReplyDelete
  14. 1].351
    2].874
    3].794

    future heisman winner a.k.a Ryder

    ReplyDelete
  15. Matt Martinez
    1. 35.1%
    2. 87.4%
    3. 63.5%

    ReplyDelete
  16. answers to evening blog post

    (1)35.1%
    (2)79.4%
    (3)87.4%

    HOWELL

    ReplyDelete
  17. Answers:

    1.)36.1%
    2.)12.6%
    3.)44.1%


    -Hart

    ReplyDelete
  18. 1. The probability of 1 occurring is .024. The probability of 2 occurring is .327.
    2. The probability of 3 not occurring is .126.
    3. The probability of 2 occurring is .327. The probability of 3 occurring is .126. The probability of 4 occurring is .341.


    Lloyd's of London

    ReplyDelete
  19. 1.) .351/1
    2.) .874/1
    3.) .794/1

    Natalie Appleton

    ReplyDelete
  20. 1 35.1%

    2 87.4%

    3 79.4%

    Graney

    ReplyDelete
  21. 1=0.351
    2=0.874
    3=0.794


    spensley

    ReplyDelete
  22. 1. 0.351
    2. 0.874
    3. 0.794

    ReplyDelete
  23. 1. 0.351
    2. 0.874
    3. 0.794


    -Sisson

    ReplyDelete
  24. 1. 35.1%
    2. 87.4%
    3. 79.4%

    Jamie Coughlin 3 period

    ReplyDelete
  25. The probability of 1 and 2 occurring is 0.351. The probability of 3 not occurring is 0.274. The probability of 2, 3, and 4 occurring is 0.794.



    your favorite student,
    BLS

    ReplyDelete
  26. 1.35.1%
    2.87.4%
    3.79.4%

    -Godlewski

    ReplyDelete
  27. 1 .351
    2 .874
    3 .794

    Forrey (Bullsye)

    ReplyDelete
  28. #1: 35.1%
    #2: 87.4%
    #3: 79.4%

    GALLAGHER 1°

    ReplyDelete
  29. 1 .351
    2 .874
    3 .794

    From Groenewagon

    ReplyDelete
  30. 1. 0.351
    2. 0.874
    3. 0.794


    Joe Corbo

    ReplyDelete
  31. 1. 35.1%
    2. 84.7%
    3. 79.4%

    ~ Gee

    ReplyDelete
  32. 1)This would be the same as 1 and 2 together or 0.351
    2)This would be the probability away from one or .874
    3. This would be all of 2,3,4 added together or .794

    Professor J. Neipp

    ReplyDelete
  33. question 1-35.1%
    question 2-87.4%
    question 3-79.4%

    Lina

    ReplyDelete
  34. 1.) 0.351
    2.) 0.874
    3.) 0.794
    Little Sunny D

    ReplyDelete
  35. 1. 0.351
    2. 0.874
    3. 0.794

    chit chat lacasse

    ReplyDelete
  36. 1.) 351/1
    2.) 874/1
    3.) 794/1

    GWAM (guay) gonna beat you in dodge ball in gym tomorrow Mr. Giomini!

    ReplyDelete
  37. Evening Practice Blog Post

    1. The probability of 1 or 2 occurring is 0.024/1 (or 24.1%) + 1.327/1 (or 32.7% = 0.351 (or 35.1%).

    2. The probability of 3 not occurring is 1.0 - 0.126 (or 12.6%) = 0.874 (or 87.4%).

    3. The probability of 2,3, or 4 occurring is 0.327/1 + 0.126/1 + 0.341 (or 34.15) = 0.794 (or 79.4%).

    ReplyDelete